多元函数二阶偏导

先上例题

设函数$f$有二阶连续偏导,且$z=f(xy,x+y)$.

$$ \frac{\partial^2z}{\partial xy} $$

分析

求二阶偏导,先求出一阶偏导。 当二阶偏导连续,有:

$$ \frac{\partial^2z}{\partial xy} = \frac{\partial (\frac{\partial x}{\partial y})}{\partial x} = \frac{\partial(\frac{\partial z}{\partial x})}{\partial y} $$

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注意到$f_1$和$f_2$均有$(xy),(x+y)$的变量

总结

对于抽象函数

$$ z = f(g_1,g_2,g_3 \dots) $$

其中,$g_1,g_2,g_3,\dots$是关于$x,y$的二元或一元函数

则,

$$ \begin{aligned} \frac{\partial z}{\partial x} & = f_1g_{1_x} + f_2g_{2_x} + f_3g_{3_x} +\dots \\ \frac{\partial^2z}{\partial xy} &= \frac{d(g_{1_x})}{dy}f_1+g_{1_x}(f_{11}\frac{\partial g_1}{\partial y}+f_{12}\frac{\partial g_2}{\partial y}+\dots) + \dots \end{aligned} $$

注意到,$f_1$仍然是包含$g_n$的函数。例如

$$ \begin{aligned} z & = f(u,v) = u^v \\ \frac{\partial z}{\partial u} &= f_1(u,v)=vu^{v-1} \end{aligned} $$
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